1/5(x+3)^2-5=0

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Solution for 1/5(x+3)^2-5=0 equation: 


x in (-oo:+oo)

(1/5)*(x+3)^2-5 = 0

1/5*(x+3)^2-5 = 0

1/5*(x+3)^2-5 = 0

1/5*x^2+6/5*x-16/5 = 0

1/5*x^2+6/5*x-16/5 = 0

1/5*(x^2+6*x-16) = 0

x^2+6*x-16 = 0

DELTA = 6^2-(-16*1*4)

DELTA = 100

DELTA > 0

x = (100^(1/2)-6)/(1*2) or x = (-100^(1/2)-6)/(1*2)

x = 2 or x = -8

1/5*(x+8)*(x-2) = 0

1/5*(x+8)*(x-2) = 0

( x+8 )

x+8 = 0 // - 8

x = -8

( x-2 )

x-2 = 0 // + 2

x = 2

x in { -8, 2 }

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